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science of city planning - /scp/ general
/help/ - Advice General
bros, am about to start college at university in the US (100% scholarship mila tha) now i have to choose. My parents don't care what I choose as long as I get some job in the next 5-10 years, but my relatives are pressuring them to tell me to choose ...
Indian research that you all look for
http://www.bikashsantra.byethost7.com/Anubhav/anubhav.html?i=1 >indian research >this guy is currently as professor at some new IIT >reserved chamar over.
+7HEPh
No.120842
2+4+8+16+......= S
2+2(2+4+8+....)= S
2+2S= S
2= -S
S= -1/2
8nTedn
No.121027
>>120842(OP)
Last step is fake and gay
WvRyOO
No.122410
>>120842(OP)
divergent
hZ+irR
No.123334
>>120842(OP)
wouldn't S be equal to -2 then? How the fuck did you get -1/2 ??
IQsSPv
No.124095
>>123334
It's wrong obv and just a reminder to all brainlets itt OP is wrong for not mentioning regularities and making it look like regular algebra
Fuck OP in the mouth
IQsSPv
No.124096
O/9AyO
No.188112
>>120842(OP)
Interesting divergent series. Just wanted to point out what you are essentially doing is the taking the following formula:
S = a(1 + r+ r^2 + ...) = a/(1-r), r<1
This formula has a pole at r =1. However you can think of the complex r plane, introduce a small imaginary part, and smoothly continue to r>1 using the same formula.
S = a/(1-r), r>1
This is a perfectly valid operation which gives you
S = -2
More generally, summing a divergent series usually goes as follows:
1. Find a region where the function converges, and derive the formula for it.
2. Continue to the complex plane and extend the function's domain, as I demonstrated above.
3. Use that answer for the divergent series as I did to get S =-2.
A classic example is Riemann zeta function: https://en.wikipedia.org/wiki/Riemann_zeta_function
>kanging moment
Ramanujam summed divergent series like anything, people have still not comprehended the magnitude of what he did.
>another funny example
See the sum
S =1+ 2 + 3 + 4 + ...
= - 1/12
here: https://en.wikipedia.org/wiki/1_%2B_2_%2B_3_%2B_4_%2B_%E2%8B%AF
