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She sent me something crazy
Uicbgm
No.524817
So basically this morning I woke up at like 8:30 am because i slept late around 2 am late at night plus i was feeling really sleepy so I woke up late and I lowkey started scrolling pinterest the moment I woke up and I came across this girl in the picture in thought she was cute.. anyways I began solving some maths paper questions after that and I came across this one question that i found kinda, confusing it's
Let a=3/2 and b= 5/66 If x, y € R are such that 5 3x+2y=log (18) 2x-y = log, (/1080), and then 4x+5y is equal to
Could anyone tell me how to solve this? I'm really struggling
szsJc0
No.524822
>>524817(OP)
(Text Content Sanitized Too.)
TflzRM
No.524825
>>524817(OP)
> given
a = 3/2
b = 5/66
> equations
3x + 2y = logₐ(18)
2x − y = log_b(1/1080)
> step 1: solve linear system
> from second
y = 2x − log_b(1/1080)
> plug into first
> 3x + 2(2x − log_b(1/1080)) = logₐ(18)
> simplify
7x − 2log_b(1/1080) = logₐ(18)
> solve x
x = (logₐ(18) + 2log_b(1/1080)) / 7
> find y
y = (2logₐ(18) − 3log_b(1/1080)) / 7
> step 2: compute target
> 4x + 5y
> substitute
> 4x + 5y
= [4(logₐ18 + 2log_b(1/1080)) + 5(2logₐ18 − 3log_b(1/1080))] / 7
> simplify numerator
> 4logₐ18 + 8log_b(1/1080)
+10logₐ18 −15log_b(1/1080)
> = 14logₐ18 − 7log_b(1/1080)
> divide by 7
> final result
> 4x + 5y = 2logₐ(18) − log_b(1/1080)
ty8FFA
No.524842
>>524837
Damn yaar you have a trad gf hope she stays like this
X50+Ey
No.524844
>>524837
and you show her off to bhachad bvlls?
Uicbgm
No.524848
>>524842
Who knows, I'm trying my luck to a better girl(she's a model) hope I succeed in wooing her
X50+Ey
No.524864
>>524851
yeah why not show off more of her? lemme see those milkers
Uicbgm
No.524869
>>524864
Fuck off creep
X50+Ey
No.524870
OSINTfags where you at?
X50+Ey
No.524873
>>524870
didnt they find a vunch of websites a while back?
TflzRM
No.524884
